![If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2, 1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) ( If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2, 1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) (](https://d10lpgp6xz60nq.cloudfront.net/ss/web/129553.jpg)
If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2, 1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) (
if the roots of the equation a(b c)x^2+b(c a)x+c(a b)=0 are equal and a,b,c>0, then prove that 2/b=1/a+1/c, i.e., a,b,c are in H.P.
Prove the following identities –|(-bc,b^2+bc,c^2+bc)(a^2+ac,-ac,c^2+ac)(a^2+ ab,b^2+ab,-ab)| = (ab + bc + ca)^3 - Sarthaks eConnect | Largest Online Education Community
![matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange](https://i.stack.imgur.com/WqPIX.jpg)
matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange
![radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange](https://i.stack.imgur.com/UVS3U.png)
radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange
![matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange](https://i.stack.imgur.com/dPZKQ.jpg)
matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange
![If Two Roots Of The Quadratic Equation (b-c) X²+(c-a)x+(a-b)=0 Are Equal, Then Let Us Prove That, 2b=a+c - ConceptEra If Two Roots Of The Quadratic Equation (b-c) X²+(c-a)x+(a-b)=0 Are Equal, Then Let Us Prove That, 2b=a+c - ConceptEra](https://conceptera.in/wp-content/uploads/2021/10/1.5-5.jpg)